MathematicsMedium64×since 2004Q4013The integral ∫sec2/3 x cosec4/3x dx\int {{\rm{se}}{{\rm{c}}^{{\rm{2/ 3}}}}\,{\rm{x }}\,{\rm{cose}}{{\rm{c}}^{{\rm{4 / 3}}}}{\rm{x \,dx}}}∫sec2/3xcosec4/3xdx is equal to (Hence C is a constant of integration)A-3/4 tan ^- 4 / 3 x + CB3tan^–1/3x + CC–3cot^–1/3x+ CD- 3tan^–1/3x + CCheck answerSkip