MathematicsEasy127×since 2002Q3037The lines 2x - 3y = 5 and 3x - 4y = 7 are diameters of a circle having area as 154 sq. units. Then the equation of the circle is :Ax2 + y2− 2x + 2y = 62{x^2}\, + \,{y^2} - \,2x\, + \,2y\,\, = \,62x2+y2−2x+2y=62Bx2 + y2+ 2x − 2y = 62{x^2}\, + \,{y^2} + \,2x\, - \,2y\,\, = \,62x2+y2+2x−2y=62Cx2 + y2+ 2x − 2y = 47{x^2}\, + \,{y^2} + \,2x\, - \,2y\,\, = \,47x2+y2+2x−2y=47Dx2 + y2− 2x + 2y = 47{x^2}\, + \,{y^2} - \,2x\, + \,2y\,\, = \,47x2+y2−2x+2y=47Check answerSkip