PhysicsMedium120×since 2002Q6764The magnetic field of a plane electromagnetic wave is B→=3×10−8sin[200π(y+ct)]i^\overrightarrow B = 3 \times {10^{ - 8}}\sin \left[ {200\pi \left( {y + ct} \right)} \right]\widehat iB=3×10−8sin[200π(y+ct)]i T where c = 3 ×\times× 10⁸ ms^–1 is the speed of light. The corresponding electric field is :AE→=−10−6sin[200π(y+ct)]k^\overrightarrow E = - {10^{ - 6}}\sin \left[ {200\pi \left( {y + ct} \right)} \right]\widehat kE=−10−6sin[200π(y+ct)]k V/mBE→=−9sin[200π(y+ct)]k^\overrightarrow E = - 9\sin \left[ {200\pi \left( {y + ct} \right)} \right]\widehat kE=−9sin[200π(y+ct)]k V/mCE→=9sin[200π(y+ct)]k^\overrightarrow E = 9\sin \left[ {200\pi \left( {y + ct} \right)} \right]\widehat kE=9sin[200π(y+ct)]k V/mDE→=3×10−8sin[200π(y+ct)]k^\overrightarrow E = 3 \times {10^{ - 8}}\sin \left[ {200\pi \left( {y + ct} \right)} \right]\widehat kE=3×10−8sin[200π(y+ct)]kCheck answerSkip