MathematicsMedium75×since 2002Q4892The mean and variance of a binomial distribution are α\alphaα and α3\frac{\alpha}{3}3α respectively. If P(X=1)=4243\mathrm{P}(X=1)=\frac{4}{243}P(X=1)=2434, then P(X=4\mathrm{P}(X=4P(X=4 or 5))) is equal to :A59\frac{5}{9}95B6481\frac{64}{81}8164C1627\frac{16}{27}2716D145243\frac{145}{243}243145Check answerSkip