PhysicsEasy159×since 2002Q7268The minimum and maximum distances of a planet revolving around the sun are x₁ and x₂. If the minimum speed of the planet on its trajectory is v₀ then its maximum speed will be :Av0x12x22{{{v_0}x_1^2} \over {x_2^2}}x22v0x12Bv0x22x12{{{v_0}x_2^2} \over {x_1^2}}x12v0x22Cv0x1x2{{{v_0}x_1^{}} \over {x_2^{}}}x2v0x1Dv0x2x1{{{v_0}x_2^{}} \over {x_1^{}}}x1v0x2Check answerSkip