MathematicsEasy210×since 2002Q3457The minimum value of the function f(x)=∫02e∣x−t∣dtf(x) = \int\limits_0^2 {{e^{|x - t|}}dt}f(x)=0∫2e∣x−t∣dt is :A2B2(e−1)2(e-1)2(e−1)Ce(e−1)e(e-1)e(e−1)D2e−12e-12e−1Check answerSkip