MathematicsMedium127×since 2002Q3091The number of common tangents to the circles x2+y2−4x−6x−12=0{x^2} + {y^2} - 4x - 6x - 12 = 0x2+y2−4x−6x−12=0 and x2+y2+6x+18y+26=0,{x^2} + {y^2} + 6x + 18y + 26 = 0,x2+y2+6x+18y+26=0, is :A333B444C111D222Check answerSkip