MathematicsEasy129×since 2002Q5104The number of real roots of the equation x2−4x+3+x2−9=4x2−14x+6\sqrt{x^{2}-4 x+3}+\sqrt{x^{2}-9}=\sqrt{4 x^{2}-14 x+6}x2−4x+3+x2−9=4x2−14x+6, is :A0B1C3D2Check answerSkip