MathematicsEasy129×since 2002Q5105The number of real solutions of the equation 3(x2+1x2)−2(x+1x)+5=03\left( {{x^2} + {1 \over {{x^2}}}} \right) - 2\left( {x + {1 \over x}} \right) + 5 = 03(x2+x21)−2(x+x1)+5=0, isA3B4C0D2Check answerSkip