MathematicsEasy38×since 2002Q3572The order and degree of the differential equation (1+3dydx)2/3=4d3ydx3\,{\left( {1 + 3{{dy} \over {dx}}} \right)^{2/3}} = 4{{{d^3}y} \over {d{x^3}}}(1+3dxdy)2/3=4dx3d3y areA(1,23)\left( {1,{2 \over 3}} \right)(1,32)B(3,1)(3, 1)(3,1)C(3,3)(3,3)(3,3)D(1,2)(1,2)(1,2)Check answerSkip