PhysicsMedium120×since 2002Q6797The oscillating magnetic field in a plane electromagnetic wave is given by By=5×10−6sin1000π(5x−4×108t)TB_{y}=5 \times 10^{-6} \sin 1000 \pi\left(5 x-4 \times 10^{8} t\right) TBy=5×10−6sin1000π(5x−4×108t)T. The amplitude of electric field will be :A15×102 Vm−115 \times 10^{2} \,\mathrm{Vm}^{-1}15×102Vm−1B5×10−6 Vm−15 \times 10^{-6} \,\mathrm{Vm}^{-1}5×10−6Vm−1C16×1012 Vm−116 \times 10^{12} \,\mathrm{Vm}^{-1}16×1012Vm−1D4×102 Vm−14 \times 10^{2} \,\mathrm{Vm}^{-1}4×102Vm−1Check answerSkip