MathematicsMedium57×since 2003Q3953The point P(−26,3)P\left( { - 2\sqrt 6 ,\sqrt 3 } \right)P(−26,3) lies on the hyperbola x2a2−y2b2=1{{{x^2}} \over {{a^2}}} - {{{y^2}} \over {{b^2}}} = 1a2x2−b2y2=1 having eccentricity 52{{\sqrt 5 } \over 2}25. If the tangent and normal at P to the hyperbola intersect its conjugate axis at the point Q and R respectively, then QR is equal to :A434\sqrt 343B6C636\sqrt 363D363\sqrt 636Check answerSkip