MathematicsMedium249×since 2002Q2510The shortest distance between the lines x−12=y+8−7=z−45{{x - 1} \over 2} = {{y + 8} \over -7} = {{z - 4} \over 5}2x−1=−7y+8=5z−4 and x−12=y−21=z−6−3{{x - 1} \over 2} = {{y - 2} \over 1} = {{z - 6} \over { - 3}}2x−1=1y−2=−3z−6 is :A232\sqrt323B333\sqrt333C434\sqrt343D535\sqrt353Check answerSkip