MathematicsEasy249×since 2002Q2544The shortest distance from the plane 12x+4y+3z=32712x+4y+3z=32712x+4y+3z=327 to the sphere x2+y2+z2+4x−2y−6z=155{x^2} + {y^2} + {z^2} + 4x - 2y - 6z = 155x2+y2+z2+4x−2y−6z=155 isA393939B262626C1141311{4 \over {13}}11134D131313Check answerSkip