MathematicsMedium38×since 2002Q3568The solution curve, of the differential equation 2ydy dx+3=5dy dx2 y \frac{\mathrm{d} y}{\mathrm{~d} x}+3=5 \frac{\mathrm{d} y}{\mathrm{~d} x}2y dxdy+3=5 dxdy, passing through the point (0,1)(0,1)(0,1) is a conic, whose vertex lies on the line :A2x+3y=−92 x+3 y=-92x+3y=−9B2x+3y=−62 x+3 y=-62x+3y=−6C2x+3y=92 x+3 y=92x+3y=9D2x+3y=62 x+3 y=62x+3y=6Check answerSkip