The solution for … of the equation … is

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Definite Integration

JEE Main 2007 · Annual, Paper 1 · Q3343

MathematicsMedium210×since 2002Q3343

The solution for

x

of the equation

\int\limits_{\sqrt 2 }^x {{{dt} \over {t\sqrt {{t^2} - 1} }} = {\pi \over 2}}

JEE Main 2007 · Annual, Paper 1 · Q3343

MathematicsMedium210×since 2002Q3343

The solution for

x

of the equation

\int\limits_{\sqrt 2 }^x {{{dt} \over {t\sqrt {{t^2} - 1} }} = {\pi \over 2}}