MathematicsMedium98×since 2002Q4820The value of ∑r=115r2(15Cr15Cr−1)\sum\limits_{r = 1}^{15} {{r^2}} \left( {{{{}^{15}{C_r}} \over {{}^{15}{C_{r - 1}}}}} \right)r=1∑15r2(15Cr−115Cr) is equal to :A560B680C1240D1085Check answerSkip