MathematicsEasy210×since 2002Q3330The value of the integral I=∫01x(1−x)ndxI = \int\limits_0^1 {x{{\left( {1 - x} \right)}^n}dx}I=0∫1x(1−x)ndx isA1n+1+1n+2{1 \over {n + 1}} + {1 \over {n + 2}}n+11+n+21B1n+1{1 \over {n + 1}}n+11C1n+2{1 \over {n + 2}}n+21D1n+1−1n+2{1 \over {n + 1}} - {1 \over {n + 2}}n+11−n+21Check answerSkip