ChemistryEasy113×since 2002Q2185The wave function (Ψ)(\Psi)(Ψ) of 2 s2 \mathrm{~s}2 s is given by Ψ2 s=122π(1a0)1/2(2−ra0)e−r/2a0\Psi_{2 \mathrm{~s}}=\frac{1}{2 \sqrt{2 \pi}}\left(\frac{1}{a_0}\right)^{1 / 2}\left(2-\frac{r}{a_0}\right) e^{-r / 2 a_0}Ψ2 s=22π1(a01)1/2(2−a0r)e−r/2a0 At r=r0r=r_0r=r0, radial node is formed. Thus, r0r_0r0 in terms of a0a_0a0Ar0=a0r_0=a_0r0=a0Br0=4a0r_0=4 a_0r0=4a0Cr0=2a0r_0=2 a_0r0=2a0Dr0=a02r_0=\frac{a_0}{2}r0=2a0Check answerSkip