PhysicsEasy56×since 2002Q6166Two capacitors C1{C_1}C1 and C2{C_2}C2 are charged to 120120120 VVV and 200200200 VVV respectively. It is found that connecting them together the potential on each one can be made zero. ThenA5C1=3C25{C_1} = 3{C_2}5C1=3C2B3C1=5C23{C_1} = 5{C_2}3C1=5C2C3C1+5C2=03{C_1} + 5{C_2} = 03C1+5C2=0D9C1=4C29{C_1} = 4{C_2}9C1=4C2Check answerSkip