PhysicsMedium202×since 2002Q8382When vector A⃗=2i^+3j^+2k^\vec{A}=2 \hat{i}+3 \hat{j}+2 \hat{k}A=2i^+3j^+2k^ is subtracted from vector B→\overrightarrow{\mathrm{B}}B, it gives a vector equal to 2j^2 \hat{j}2j^. Then the magnitude of vector B→\overrightarrow{\mathrm{B}}B will be :A3B33\sqrt{33}33C6\sqrt66D5\sqrt55Check answerSkip