Hydrogen

Which one of the following process will produce hard water?

The temporary hardness of water is due to :

100 mL of a water sample contains 0.81 g of calcium bicrabonate and 0.73 g of magnesium bicarbonate. The hardness of this water sample expressed in terms of equivalents of CaCO₃ is : (Molar mass of calcium bicarbonate is 162 g mol^–1 and magnesium bicarbonate is 146 g mol^–1)

The temporary hardness of a water sample is due to compound X. Boiling this sample converts X to compound Y. X and Y, respectively, are :

In comparison to the zeolite process for the removal of permanent hardness, the synthetic resins method is :

Amongst the following, the form of water with the lowest ionic conductance at 298 K is :

The one that is NOT suitable for the removal of permanent hardness of water is :

The functional groups that are responsible for the ion-exchange property of cation and anion exchange resins, respectively, are :

Which one of the following methods is most suitable for preparing deionized water?

Boiling of hard water is helpful in removing the temporary hardness by converting calcium hydrogen carbonate and magnesium hydrogen carbonate to :

Given below are two statements : Statement I : H₂O₂ can act as both oxidising and reducing agent in basic medium. Statement II : In the hydrogen economy, the energy is transmitted in the form of dihydrogen. In the light of the above statements, choose the correct answer from the options given below :

The metal salts formed during softening of hardwater using Clark's method are :

The products obtained during treatment of hard water using Clark's method are :

Given below are two statements : Statement I : Permutit process is more efficient compared to the synthetic resin method for the softening of water. Statement II : Synthetic resin method results in the formation of soluble sodium salts. In the light of the above statements, choose the most appropriate answer from the options given below:

NaH is an example of :

The correct statements among (a) to (d) are : (a) saline hydrides produce H₂ gas when reacted with H₂O. (b) reaction of LiAlH₄ with BF₃ leads to B₂H₆. (c) PH₃ and CH₄ are electron - rich and electron - precise hydrides, respectively. (d) HF and CH₄ are called as molecular

If the boiling point of H₂O is 373 K, the boiling point of H₂S will be :

Match List I with List II .tg {border-collapse:collapse;border-spacing:0;} .tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; overflow:hidden;padding:10px 5px;word-break:normal;} .tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;} .tg .tg-c3ow{border-color:inherit;text-align:center;vertical-align:top} .tg .tg-7btt{border-color:inherit;font-weight:bold;text-align:center;vertical-align:top} .tg .tg-0pky{border-color:inherit;text-align:left;vertical-align:top} LIST I Type of Hydride LIST II Example A. Electron deficient hydride I. $$\mathrm{MgH_2}$$ B. Electron rich hydride II. $$\mathrm{HF}$$ C. Electron precise hydride III. $$\mathrm{B_2H_6}$$ D. Saline hydride IV. $$\mathrm{CH_4}$$ Choose the correct answer from the options given below:

Which hydride among the following is less stable?