MathematicsHard115×since 2008Q4352If the truth value of the Boolean expression ((p∨q)∧(q→r)∧(∼r))→(p∧q)\left( {\left( {p \vee q} \right) \wedge \left( {q \to r} \right) \wedge \left( { \sim r} \right)} \right) \to \left( {p \wedge q} \right)((p∨q)∧(q→r)∧(∼r))→(p∧q) is false, then the truth values of the statements p, q, r respectively can be :AT F TBF F TCT F FDF T FCheck answerSkip