MathematicsMedium115×since 2008Q4364Let Δ\DeltaΔ, ∇\nabla∇ ∈\in∈ {∧\wedge∧, ∨\vee∨} be such that p ∇\nabla∇ q ⇒\Rightarrow⇒ ((p Δ\DeltaΔ q) ∇\nabla∇ r) is a tautology. Then (p ∇\nabla∇ q) Δ\DeltaΔ r is logically equivalent to :A(p Δ\DeltaΔ r) ∨\vee∨ qB(p Δ\DeltaΔ r) ∧\wedge∧ qC(p ∧\wedge∧ r) Δ\DeltaΔ qD(p ∇\nabla∇ r) ∧\wedge∧ qCheck answerSkip