MathematicsEasy115×since 2008Q4384Let Δ,∇∈{∧,∨}\Delta ,\nabla \in \{ \wedge , \vee \}Δ,∇∈{∧,∨} be such that (p→q)Δ(p∇q)\mathrm{(p \to q)\Delta (p\nabla q)}(p→q)Δ(p∇q) is a tautology. ThenAΔ=∨,∇=∨\Delta = \vee ,\nabla = \veeΔ=∨,∇=∨BΔ=∨,∇=∧\Delta = \vee ,\nabla = \wedgeΔ=∨,∇=∧CΔ=∧,∇=∧\Delta = \wedge ,\nabla = \wedgeΔ=∧,∇=∧DΔ=∧,∇=∨\Delta = \wedge ,\nabla = \veeΔ=∧,∇=∨Check answerSkip