MathematicsMedium115×since 2008Q4388Negation of p∧(q∧∼(p∧q))p \wedge(q \wedge \sim(p \wedge q))p∧(q∧∼(p∧q)) is :A(∼(p∧q))∧q(\sim(p \wedge q)) \wedge q(∼(p∧q))∧qB(∼(p∧q))∨p(\sim(p \wedge q)) \vee p(∼(p∧q))∨pCp∨qp \vee qp∨qD∼(p∨q)\sim(p \vee q)∼(p∨q)Check answerSkip