MathematicsEasy115×since 2008Q4397Statement (P⇒Q)∧(R⇒Q)\mathrm{(P \Rightarrow Q) \wedge(R \Rightarrow Q)}(P⇒Q)∧(R⇒Q) is logically equivalent to :A(P⇒R)∧(Q⇒R)(P \Rightarrow R) \wedge(Q \Rightarrow R)(P⇒R)∧(Q⇒R)B(P⇒R)∨(Q⇒R)(P \Rightarrow R) \vee(Q \Rightarrow R)(P⇒R)∨(Q⇒R)C(P∧R)⇒Q(P \wedge R) \Rightarrow Q(P∧R)⇒QD(P∨R)⇒Q(P \vee R) \Rightarrow Q(P∨R)⇒QCheck answerSkip