MathematicsEasy115×since 2008Q4313The Boolean expression (p∧∼q)∨q∨(∼p∧q)\left( {p \wedge \sim q} \right) \vee q \vee \left( { \sim p \wedge q} \right)(p∧∼q)∨q∨(∼p∧q) is equivalent to :A∼p∧q{ \sim p \wedge q}∼p∧qBp∧q{p \wedge q}p∧qCp∨qp \vee qp∨qDp∨∼qp \vee \sim qp∨∼qCheck answerSkip