MathematicsEasy115×since 2008Q4394The negation of the statement (p∨q)∧(q∨(∼r))(p \vee q) \wedge (q \vee ( \sim r))(p∨q)∧(q∨(∼r)) is :A((∼p)∨r))∧(∼q)(( \sim p) \vee r)) \wedge ( \sim q)((∼p)∨r))∧(∼q)B(p∨r)∧(∼q)(p \vee r) \wedge ( \sim q)(p∨r)∧(∼q)C((∼p)∨(∼q))∨(∼r)(( \sim p) \vee ( \sim q)) \vee ( \sim r)((∼p)∨(∼q))∨(∼r)D((∼p)∨(∼q))∧(∼r)(( \sim p) \vee ( \sim q)) \wedge ( \sim r)((∼p)∨(∼q))∧(∼r)Check answerSkip