MathematicsMedium115×since 2008Q4393The statement ∼[p∨(∼(p∧q))]\sim[p \vee(\sim(p \wedge q))]∼[p∨(∼(p∧q))] is equivalent to :A(∼(p∧q))∧q(\sim(p \wedge q)) \wedge q(∼(p∧q))∧qB∼(p∨q)\sim(p \vee q)∼(p∨q)C(p∧q)∧(∼p)(p \wedge q) \wedge(\sim p)(p∧q)∧(∼p)D∼(p∧q)\sim(p \wedge q)∼(p∧q)Check answerSkip